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Hi I have a question about this three question I already did two but I am not sure if its right

Hi I have a question about this three question I already did two but I am not sure-example-1
User Alan McBee
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1 Answer

4 votes

We have to express the probabilities as unreduced fractions.

The probability of choosing a person who has a Ford and has no complaints.

We can calculate the probability as the qoutient between the successful events and the total events.

The successful events are the persons that have a Ford and has no complaints. This number is 60.

The total number of persons we can choose from is 500.

Then, the probability is 60/500.

It can be reduced as:


P=(60)/(500)=((60)/(10))/((500)/(10))=(6)/(50)=((6)/(2))/((50)/(2))=(3)/(25)

The probability of choosing a person who has a Ford or has No complaints.

In this case the number of successful events is the sum of the people that has a Ford (95 persons) and the people that has no complaints (178 persons).

Then, the probability is:


P=(178+95)/(500)=(273)/(500)

The probability of choosing a person who does not have a Ford.

The successful events in this case is the total (500) minus the people that have a Ford (95).

Then, the probability is:


P=(500-95)/(500)=(405)/(500)=((405)/(5))/((500)/(5))=(81)/(100)

Answer:

a) P = 3/25

b) P = 273/500

c) P = 81/500

User CodingInMyBasement
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