Answer
11302.2 joules
Step-by-step explanation
Given:
Mass of water = 30.0 g
Initial temperature, T₁ = 10⁰ C
Final temperature, T₂ = 100⁰ C
Increase in temperature, ΔT = T₂ - T₁ = 100⁰ C - 10⁰ C = 90⁰ C
What to find:
The energy in joules required to increase the temperature of the water.
Step-by-step solution:
The joules required to increase the temperature of the water can be calculated using the formula:
q = mcΔT
Where q is the joules of energy required.
m is the mass of water = 30.0 g
c is the specific heat of water = 4.186 J/g ⁰C
ΔT is the temperature rise = 90 ⁰C
∴ q = 30.0 g x 4.186 J/g ⁰C x 90 ⁰C
q = 11302.2 joules
Hence, 11302.2 joules are required to increase the temperature of 30.0 g of water from 10⁰ C to 100⁰ C vapors.