Question

A student starts at position (4, 4) m and undergoes three displacements:d1= (2, - 3) m, d2 = (- 5, 0) * m , and d3= (1, 6) * m

Answer 1

Initial position ( 4, 4 )

Add the displacements

d1 ( 2 , - 3 ) = ( 4 + 2 , 4 - 3 ) = ( 6 , 1 )

d2 ( -5,0 ) = ( 6 - 5, 1 + 0 ) = (1,1 )

d3 (1, 6 ) = ( 1 + 1 , 1 + 6 ) = ( 2 , 7 )

Final position (2, 7 )

Graph: