2)
x=-1
y=-1
Step-by-step explanation
when you have a system of 2 equations and 2 variables ( x and y ), to solve the systme graph each line and the point where the lines intersect each other is the solution
![\begin{gathered} y=4x+3\text{ Equation(1)} \\ y=-x-2\text{ Equation(2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ye6yx9mszww4hy3mlbnxhbw4mwgt9g3h3f.png)
Step 1
graph equation 1 (green)
find two points
a) when x= 0
![\begin{gathered} y=4x+3 \\ y=4\cdot0+3 \\ y=0+3 \\ y=3 \\ \text{the coordinate is (0,3)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jni1pxzirmiwca38bww9uygxgxsm4fller.png)
b) when x= 2
![\begin{gathered} y=4x+3 \\ y=4\cdot2+3 \\ y=8+3 \\ y=11 \\ \text{the coordinate is (2,11)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yvup58zzyqkeultqeehvrq158ufx61hz4q.png)
now, draw a line that passes thougth the points (0,3) and (2,11)
Step 2
now, do the same for equation (2)(blue)
when x=0
![\begin{gathered} y=-x-2 \\ y=0-2 \\ y=-2 \\ \text{the coordinate is (0,-2)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/5is5txxo8615nj9pf68rrcpxtrxcfg1wc1.png)
when x=2
![\begin{gathered} y=-x-2 \\ y=-2-2 \\ y=-4 \\ \text{the coordinate is (2,-4)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hjq49swcby6zta18jknj0n9dksss1yuzpr.png)
now, draw a line that passes thougth the points (0,-2) and (2,-4).(blue line)
the answer is the point where the lines intersect each other so, the answer is
![\begin{gathered} (-1,-1) \\ or \\ x=-1 \\ y=-1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r6hwbkwvi4xp8rjp6jkipxa71zruohx78p.png)
I hope this helps you