Triangle DEF is congruent to triangle XYZ because triangle DEF is a dilation of triangle XYZ.
The previous can be shown by estimating the dilation scale factor.
The length of segment XY is 2 units.
The length of the segment YZ is
![YZ=\sqrt[]{0.5^(2)+0.5^(2)}=\sqrt[]{0.5}=0.707](https://img.qammunity.org/2023/formulas/mathematics/college/9dd5ciakngk98tom19de5ii8f495pk9lvv.png)
The length of the segment DE is 4 units.
The length of the segment EF is:
![EF=\sqrt[]{1^(2)+1^(2)}=\sqrt[]{2}=1.414](https://img.qammunity.org/2023/formulas/mathematics/college/mllzhbfymsdg71hf7lmn942lugxqz76x66.png)
You can notice that DE = 2XY and EF = 2YZ, the same happens for DF and XZ.
Hence, triangle DEF is congruent to triangle XYZ.