Question

Let f(x)=x^2+2 and g(x)=1-3x. Find each function value:
(fg)(-1)

Answer 1

12

Explanation:

`f(x)=x^2+2`

`g(x)=1-3x`

`(fg)(x)=f(x) * g(x)`

`\implies (fg)(x)=(x^2+2)(1-3x)`

`(fg)(-1)=((-1)^2+2)(1-3(-1))`

`\implies (fg)(-1)=(1+2)(1+3)`

`\implies (fg)(-1)=12`

Extra:

If you were looking for f[g(-1)], then:

`f[g(-1)]=f(4)=4^2+2=18`