Let f(x)=x^2+2 and g(x)=1-3x. Find each function value: (fg)(-1)

asked Jan 13, 2023 141k views

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Let f(x)=x^2+2 and g(x)=1-3x. Find each function value:
(fg)(-1)

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Answer:

Explanation:

f(x)=x^2+2

g(x)=1-3x

(fg)(x)=f(x) * g(x)

$\implies (fg)(x)=(x^2+2)(1-3x)$

(fg)(-1)=((-1)^2+2)(1-3(-1))

$\implies (fg)(-1)=(1+2)(1+3)$

$\implies (fg)(-1)=12$

Extra:

If you were looking for f[g(-1)], then:

f[g(-1)]=f(4)=4^2+2=18

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