We must solve the quadratic equation
4x² + 98 = 0
using the quadratic formula.
First simplify the equation by dividing both sides by 2:
2x² + 49 = 0
Identify the coeficients:
a = 2
b = 0
c = 49
Calculate delta:
Δ = b² - 4ac
Δ = 0 - 4.2.49
Δ = 0 - 392
Δ = -392
Now let's apply the quadratic formula:
x = (-b ± √Δ) / 2a
x = (-0 ± √-392) / 4
x = ± 14√2i / 4
x = ± 7√2i / 2
So
x' = -7√2i / 2
x'' = 7√2i / 2
Answer: the roots are x' = -7√2i / 2 and x'' = 7√2i / 2