Question

Evaluate the expression how do you get to (2^-1 x 3^0)^3 times (2^0 x 5^3) ^5

Answer 1

we have the expression

`(2^(-1)\cdot3^0)^(-3)\cdot(2^0\cdot5^3)^5`

Remember that

`\begin{gathered} 2^(-1)=(1)/(2) \\ 3^0=1 \\ 2^0=1 \\ 5^3=125 \end{gathered}`

substitute in the original expression

`\begin{gathered} ((1)/(2)\cdot1)^(-3)\cdot(1\cdot125)^5 \\ ((1)/(2)\cdot)^(-3)\cdot(125)^5 \end{gathered}`
`\begin{gathered} ((1)/(2))^(-3)=2^3=8 \\ \end{gathered}`

substitute

`\begin{gathered} 8\cdot(125)^5 \\ 8\cdot30,517,578,125 \\ 244,140,625,000 \end{gathered}`

therefore

The answer is

244,140,625,000