The dimension of the cardboard is 12in by 5in
So when the cardboard is curved into a cylinder
there are two ways to do that
If diagram 'a' is folded into a cylinder
the circunference of the circular base form is 5 inches
then the radius is 0.8 in
since circuference = 2x pi x r
If diagram 'b' is folded into a cylinder
the circumference of the circular base is 12 inches
then the radius is 1.9 in
the volume
![\text{volume of a cylinder=}\pi* r^2* h](https://img.qammunity.org/2023/formulas/mathematics/high-school/rzeeafi5sx02fzagm9uwga0tlhrstffhip.png)
![\begin{gathered} \text{for diagram 'a'} \\ \text{volume = 3.142}*0.8^2*12=24.1in^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/chpq5i1snnxneqp0r3rokx4x8nifc2cn3v.png)
![\begin{gathered} \text{for diagram 'b'} \\ \text{volume = 3.142 }*1.9^2*5=56.7in^3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/yj3es82umxc2e0zylzz8z8vvpo7l40piw2.png)
So diagram b gives the larger volume
Hence, when the cardboard in curved in such a way that the 12 inches side forms the base, the volume is larger than when the cardboard is curved such that the 5 inches side forms the base