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Write an equation of a line through the point (-5, -2)that is perpendicular to the x-axis. Also state the slope of the line. A. x = -5, m = 0B. y = -2, m = 0C. x = -5, m = undefinedD. y = -2, m = undefined

User Feitla
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1 Answer

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First let's take a look at the point (-5,-2) in the plane:

since we want an equation of a line that is perpendicular to the x-axis, it should look like this:

Therefore, the equation is x = -5. Now for the slope, we can easily see that the line passes through the points (-5,-2) and (-5,-3), so, if we calculate the slope we get something like this:


\begin{gathered} m=(y_2-y_1)/(x_2-x_1)_{} \\ \Rightarrow m=(-3.-(-2))/(-5-(-5))=(-3+2)/(-5+5)=-(1)/(0) \end{gathered}

which clearly is undefined.

Write an equation of a line through the point (-5, -2)that is perpendicular to the-example-1
Write an equation of a line through the point (-5, -2)that is perpendicular to the-example-2
User Filomat
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