Step-by-step explanation
We have a total of 26 in the standard alphabet, 5 of them are vowel and the remaining 21 are consonants.
Also, we have 9 non-zero numbers.
The restrictions don't mention that we can't repeat letters or numbers, so we will assume we can repeat.
Since the first 2 spaces are consonants, we can pick each of them from 21 possibilities, so the combinations for that part are:
![21\cdot21](https://img.qammunity.org/2023/formulas/mathematics/college/esx0a0tsz8emtaax5w0obepnuesk7dsway.png)
The next three are the non-zero numbers, so we can pick each from 9 possibilities:
![21\cdot21\cdot9\cdot9\cdot9](https://img.qammunity.org/2023/formulas/mathematics/college/78s1x48020e741v6laj88gdhaqnxrd2uj8.png)
And the last is a vowel, so we can only pick from the 5 possibilities, so we have:
![21\cdot21\cdot9\cdot9\cdot9\cdot5](https://img.qammunity.org/2023/formulas/mathematics/college/sisocqqr0g1cy8r3qhmgc8nxfswddgqo7z.png)
These are all the possibilities, so we just need to evaluate the product:
![21\cdot21\cdot9\cdot9\cdot9\cdot5=1,607,445](https://img.qammunity.org/2023/formulas/mathematics/college/mzkvqkukfzditibtr4x35lfhuo37iqgwc1.png)
Answer
So, there are 1,607,445 possibilities.