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The height of a rectangular box is 4ft. The length is 2 ft longer than thrice the width x . The volume is 480^3

what's the length and the width

The height of a rectangular box is 4ft. The length is 2 ft longer than thrice the-example-1

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SOLUTION

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\begin{gathered} \text{height of the box h = 4ft} \\ \text{width = x} \\ \text{length = 2 + 3x} \\ \text{Volume = 224ft}^3 \end{gathered}

Since the length is 2ft longer than trice the width, the length = 2 + 3x, since the width is given as x.

Now, the box is a cuboid. volume of a cuboid is given as


V=length* width* height

So the equation becomes


\begin{gathered} V=l* x* h \\ 224=(2+3x)* x*4 \\ 224=(2+3x)4x \\ 224=8x+12x^2 \\ \\ 12x^2+8x-224=0 \end{gathered}

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