Question

Geometry question about trig ratios Solve for x. Round to the nearest tenth.

Answer 1

Step-by-step explanation:

To get the value of x, we will use the trigonometric ratio

`\cos \theta=(adjacent)/(hypotenuse)`

The value of x will be obtained as

`\cos 64^0=(x)/(11)`

Making x, the subject of the formula

`\begin{gathered} x=11*\cos 64^0 \\ x=4.8\text{ (To the nearest tenth)} \end{gathered}`

The value of x is 4.8 (To the nearest tenth)