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Geometry question about trig ratios Solve for x. Round to the nearest tenth.

Geometry question about trig ratios Solve for x. Round to the nearest tenth.-example-1
User Sagheer
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1 Answer

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Step-by-step explanation:

To get the value of x, we will use the trigonometric ratio


\cos \theta=(adjacent)/(hypotenuse)

The value of x will be obtained as


\cos 64^0=(x)/(11)

Making x, the subject of the formula


\begin{gathered} x=11*\cos 64^0 \\ x=4.8\text{ (To the nearest tenth)} \end{gathered}

The value of x is 4.8 (To the nearest tenth)

User Wienke
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