We are going to use long division to found the remainder
Find an expression that multiplies by x-5, we can cancel the x^3, we use the same sign because when we pass to operate the sing change, like this:
x^2(x-5) = x^3-5x^2
Now, x^3 - x^2
-x^3+5x^2
--------------------
0 +4x^2
Find an expression to cancel 3x^2 using the dividend x-5:
4x(x-5)= 4x^2 -20x
Operate:
4x^2 -17x
-4x^2 +20x
------------------
0+3x
Find an expression to cancel 3x
3(x-5)= 3x-15
Operate:
3x-15
-3x+15
-------------
0
So , the remainder is 0
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