Question

Write an equation in slope intercept form of the line that bisects the angle formed by KJ and KLy=

Answer 1

y=-x+1

1) Since this line must bisect ∠LKJ then we can locate two points that belong to the line that divides equally ∠LKJ like point (3,-2) and (2,-1).

2) We can now proceed with that to find the slope of that line:

`m=(y_2-y_1)/(x_2-x_1)=(-1-(-2))/(2-3)=(-1+2)/(-1)=(1)/(-1)=-1`

3) With the slope and one point we can find the linear coefficient plugging into the slope-intercept formula:

Plugging point (3,-2) and slope m=-1 we have:

y=mx + b

-2=3(-1)+b

-2=-3+b

-2+3 =b

b=1

Hence the the equation written in the slope-intercept formula is:

y=-x+1