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of one hundred and forty two students attending college , 23 are criminal justice majors. if 9 are selected at random, determine the probability each 9 criminal justice major. set up the problem as if it were to be solved but don't solve.

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The probablity that first one selected is a criminal justice major is,


P_1=(23)/(142)

Now, the probablity that second one is a criminal justice major is when selected without replacement,


P_2=(22)/(141)

Simirally,


\begin{gathered} P_3=(21)/(140) \\ P_4=(20)/(139) \\ \ldots.\text{.} \end{gathered}

Thus, using the multiplication theorem,


\begin{gathered} P=P_1* P_2*\ldots\ldots.P_9 \\ =(23)/(142)*(22)/(141)*(21)/(140)*\ldots\ldots\ldots\ldots\ldots(15)/(134) \end{gathered}

Thus, the above equation gives the requried probablity.

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