Since the area of square A is 97 square inches, then it follows that the sides of A are:
![a=\sqrt[]{97}](https://img.qammunity.org/2023/formulas/mathematics/college/sv3ex0q0hqy995qzfpdykx7xh0xjvf3j1y.png)
And since the area of square B is 24 square inches, then it follows that the sides of B are:
![b=\sqrt[]{24}](https://img.qammunity.org/2023/formulas/mathematics/college/98vsdzw8rkpp1msf2y8ua0ehu6kpw0w8p5.png)
Then, we can note from the image that the side of C is the hypothenuse of a triangle with it's sides equal to a side of A and a side of B, then for the Pythagoras theorem we have that:
![c^2=(\sqrt[]{97})^2+(\sqrt[]{24})^2](https://img.qammunity.org/2023/formulas/mathematics/college/1qid9m1qdpvdk5ltwjjqza5m306tvmojff.png)
then
![c=\sqrt[]{121}](https://img.qammunity.org/2023/formulas/mathematics/college/ayp2d4ltqlqb3e6cltq2wmtfm4ure0ilhk.png)
where c is the length of the sides of C.
then the area of the triangle C is:
![\text{AreaC}=(\sqrt[]{121})^2=121\text{ square inches}](https://img.qammunity.org/2023/formulas/mathematics/college/lm12hga0o4bypst456rq409qbrwht8j67k.png)