88.1k views
3 votes
-4x + y = 13-5x + 8y = -4

User Rbatt
by
8.2k points

1 Answer

6 votes
System of equations by substitution

We want to know if there is any form for both equations to have the same x and y

-4x + y = 13

-5x + 8y = -4​

Step 1: we find an expression for y

We solve one of the equations for x or y. In this case we are solving the first for y:

-4x + y = 13

↓ taking -4x to the right side

y = 13 + 4x

Step 2: finding an equation with just one unkown, x

In order to find an equation with just one unkown we replace y = 13 + 4x

on the other equation, the second equation:

-5x + 8y = -4​

↓ replacing y by 13 + 4x

-5x + 8(13 + 4x) = -4​

↓ since 8(13 + 4x) = 104 + 32x

-5x + 104 + 32x = -4​

↓ since -5x + 32x = 27x

104 + 27x = -4​

Step 3: finding x

Using the equation found we are going to find x

104 + 27x = -4​

↓ taking 104 to the right side

27x = -4​ - 104

↓ since -4 - 104 = -108

27x = -108

↓ taking 27 to the right side

x = -108/27

↓ since -108/27 = -4

x = -4

Step 4: finding y

Now, we just replace the value for x we found in any of the equations (we must have the same result on both):

in the first equation...

-4x + y = 13

↓ replacing x = -4

-4(-4) + y = 13

↓ since -4(-4) = 16

16 + y = 13

↓ taking 16 to the right side

y = 13 - 16 = -3

Then, the solution is when x = -4 and y = -3

Answer: (-4, -3)

User Deeenes
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories