If angles C and D are the acute angles of a right triangle, we have the image as shown below:
The question gives that:

Comparing with the Sine Trigonometric Ratio given to be:

we thus have that the Sine ratio of angle D in the triangle drawn above will be:

Hence, we can have the triangle look as shown below:
Therefore, the cosine of angle C, with the ratio:

will be given to be:

Therefore, the correct option is the FIRST OPTION.