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In ΔJKL, m∠J = (8x−7)°, m∠K= (x + 7)°, and m∠L = (2x+15)∘. What is the value of x?
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In ΔJKL, m∠J = (8x−7)°, m∠K= (x + 7)°, and m∠L = (2x+15)∘. What is the value of x?

User Nazli
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1 Answer

4 votes

Answer:

15

Explanation:

In ΔJKL, m∠J = (8x−7)°, m∠K= (x + 7)°, and m∠L = (2x+15)∘. What is the value of x-example-1
User Earnshavian
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