Question

Please help check clarification. I have attached pictures. Thank you!

Answer 1

Given the exponential function

`A(t)=A_0e^(-0.316t)`

Take

`A_0=550`

Then

`A(t)=550e^(-0.316t)`

Substitute 0 for t into A(t).

`\begin{gathered} A(0)=550e^0 \\ =550 \end{gathered}`

Substitute 1 for t into A(t).

`\begin{gathered} A(1)=550e^(-0.316) \\ =400.983 \end{gathered}`

Substitute 2 for t into A(t).

`\begin{gathered} A(2)=550e^(-0.316\cdot2) \\ =265.764 \end{gathered}`

Substitute 3 for t into A(t).

`\begin{gathered} A(3)=550e^(-0.316\cdot\cdot3) \\ =193.758 \end{gathered}`

Substitute 4 for t into A(t).

`\begin{gathered} A(4)=550e^(-0.316\cdot\cdot4) \\ =141.261 \end{gathered}`

Substitute 5 for t into A(t).

`\begin{gathered} A(5)=550e^(-0.316\cdot\cdot5) \\ =102.988 \end{gathered}`

Substitute 6 for t into A(t).

`\begin{gathered} A(6)=550e^(-0.316\cdot\cdot6) \\ =75.084 \end{gathered}`

Substitute 10 for t into A(t).

`\begin{gathered} A(10)=550e^(-0.316\cdot10) \\ =21.213 \end{gathered}`

Substitute 20 for t into A(t).

`\begin{gathered} A(20)=550e^(-0.316\cdot20) \\ =0.89997 \end{gathered}`

Substitute 25 for t into A(t).

`\begin{gathered} A(25)=550e^(-0.316\cdot25) \\ =0.1854 \end{gathered}`

Substitute 30 for t into A(t).

`\begin{gathered} A(30)=550e^(-0.316\cdot30) \\ =0.042 \end{gathered}`