1 Answer

Steve Landey · Answer 1 · 2023-04-21T07:44:34+0000

From the question;

A technical mechinist is asked to build a cubical steel tank that will hold 220L of water

this implies

$\text{Volume of water = 220L}$

Using the formula of volume of cube

$\text{volume of cube = l}^3$

converting Liters to cubic meter

WE have

$220\text{ L = }0.22m^3$

Hence

$Volumeofcubical-\tan k=0.22m^3$

Finding the length

$\begin{gathered} l^3=0.22m^3 \\ l=\sqrt[3]{0.22m^3^{}} \\ l=0.604m \end{gathered}$

Hence the smallest possible inside length of the cubical tank is 0.604m

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