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A set contains three consecutive numbers. The sum of these three numbers is 54. Wat are the three numbers16, 17, 1815, 16, 1717, 18, 19

User Jove
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1 Answer

2 votes

Let be "x" the first number of the set that contains three consecutives numbers whose sum is 54. The others two numbers can be represented as:


\begin{gathered} x+1 \\ x+2 \end{gathered}

According to the exercise, when you add these three consecutives numbers, you get 54 as the result of the addition. Based on this, you can write the following equation:


x+(x+1)+(x+2)=54

Now you have to solve for "x":


\begin{gathered} x+x+1+x+2=54 \\ 3x+3=54 \\ 3x=54-3 \\ 3x=51 \\ x=(51)/(3) \\ x=17 \end{gathered}

Substituting this value, you get that the others numbers are:


\begin{gathered} x+1=17+1=18 \\ x+2=17+2=19 \end{gathered}

So the three numbers are:


17,18,19

The answer is the last option.

User Cmccabe
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