Answer
Probability of drawing an ace given that it is diamond = (1/13)
Step-by-step explanation
There are 52 cards in a pack of cards.
In this pack, there are 13 diamonds and 4 aces.
But there is only 1 ace diamond.
Since the probability of an event A occuring given that an event B has occured is given mathematically as
P (A | B) = P (A n B) ÷ P (B)
In this case, event A is the probability that the card picked is an ace and event B is given that the card picked is a diamond.
P (A n B) refers to the probability of picking a card that is both ace and a diamond.
Since there's only one of such in a pack of cards (52 cards),
P (A n B) = (1/52)
P(B) refers to the probability that the card picked is a diamond.
Since there's 13 diamonds in a pack of cards (52 cards),
P (B) = (13/52)
Probability of drawing an ace given that it is diamond
= P (A | B)
= P (A n B) ÷ P (B)
= (1/52) ÷ (13/52)
= (1/52) × (52/13)
= (1/13)
Hope this Helps!!!