Question

Write an equation of the line that passes through the point (5.6) with slope 3

Answer 1

step 1

The equation of the line in slope-intercept form is given by

`y=mx+b`

In this problem we have

m=3

point (5,6)

substitute and solve for b

`\begin{gathered} 6=3(5)+b \\ 6=15+b \\ b=6-15 \\ b=-9 \end{gathered}`

therefore

The equation of the line is

`y=3x-9`

Find out the equation in point-slope form

`y-y_1=m(x-x_1)`

we have

m=3

point (5,6)

substitute

`y-6=3(x-5)`

The answer is option B