Question

I’m an isosceles triangle, one angle is 18 degrees greater than each of the other two equal angles. Find the measure of all thee angles.

Answer 1

In an isosceles triangle, there's a pair of congruent angles. Let's call x each of these congruent angles.

Since one angle is 18 degrees greater than each of the other two equal angles, this third angle is given by:

x + 18º

Now, we need to use the property that the three internal angles in a triangle must sum up to 180º. Then, we have:

x + x + (x + 18º) = 180º

Then, solving this equation, we find:

x + x + (x + 18º) = 180º

3x + 18º = 180º

3x + 18º - 18º = 180º - 18º

3x = 162º

3x/3 = 162º/3

x = 54º

And the third angle is

x + 18º = 54º + 18º = 72º

Therefore, the angles are:

54º, 54º, and 72º