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Find the Lateral Area and Surface Area of the figure.1310Perimeter of the base =Slant height = _ (Note: 13 is NOT the slant height)Area of the base = _square unitsL.A. = _square unitsS.A. = _ square unitsFind the Lateral Area and Surface Area of the figure.1310Perimeter of the base =✓ 40Slant height =12 (Note: 13 is NOT the slant height)Area of the base = 100 square unitsL.A. = X 480 square unitsS.A. = X 580 square units

Find the Lateral Area and Surface Area of the figure.1310Perimeter of the base =Slant-example-1
User Mukund
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L.A. = 240 square units

S.A. = 340 square units

Step-by-step explanation:

Lateral area of triangular pyramid = 1/2 (perimter of base × slant height)

perimter of base = 40

slant height = 12


\begin{gathered} \text{lateral area = L.A = }(1)/(2)(40\text{ }*\text{ }12) \\ L\mathrm{}A.\text{ = 480/2} \\ L.A.\text{ = }240\text{ square units} \end{gathered}

Surface area of triangular pyramid = base area + 1/2(perimeter × slant height)

base area = 100 suqrae units

1/2(perimeter × slant height) = L.A. = 240 square units


\begin{gathered} \text{Surface area = 100 + 240} \\ \text{Surface area = S.A. = 340} \\ S\mathrm{}A.\text{ =340 square units} \end{gathered}

User Bhavesh B
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