The area of a rectangle is calculated using the formula:
![A=l* w](https://img.qammunity.org/2023/formulas/mathematics/college/lmmzpu3pbc5f31ild3jzkycy7t9l4cj8y8.png)
where l is the length and w is the width.
The functions for the length and width are given to be:
![\begin{gathered} l(x)=2x+1 \\ w(x)=x+4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/cuuri8j2yha9cw8y3vcqj4x1wu87z3tltg.png)
Therefore, the area of the rectangle will be:
![A=(2x+1)(x+4)](https://img.qammunity.org/2023/formulas/mathematics/college/1jnbb1uptehg3foesehoh8abkhz8sgzuow.png)
We can apply the FOIL Method:
![(a+b)(c+d)=ac+ad+bc+bd](https://img.qammunity.org/2023/formulas/mathematics/high-school/kuxpyq84a5afz3rajtbhk4ynou3aar7oyu.png)
Therefore, we have:
![\begin{gathered} \left(2x+1\right)\left(x+4\right)=2x\cdot x+2x\cdot\:4+1\cdot\:x+1\cdot\:4 \\ =2x^2+8x+x+4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/hdh13xe7omfyem8230w1qydvp6o1lju3kv.png)
Simplifying, the area is:
![a(x)=2x^2+9x+4](https://img.qammunity.org/2023/formulas/mathematics/college/n288gi29m6t7rjdgm9eyuefirg20au1vxk.png)
The SECOND OPTION is correct.