Answer:
The resulting velocity = 346.41 m/s
Explanations:
The rocket is initially at rest
The initial speed, v₀ = 0 m/s
The acceleration, a = 20 m/s²
The distance covered, S = 3000m
To get the final velocity, use the equation of motion written below

Substitute v₀ = 0 m/s, a = 20 m/s², and S = 3000m into the formula above
![\begin{gathered} v^2=0^2\text{ + 2(20)(3000)} \\ v^2\text{ = }120000 \\ v=\text{ }\sqrt[]{120000} \\ v\text{ = }346.41m/s^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/pcnb9q53kjgvkrrdzuyswvby8d7d0xzp2t.png)
The resulting velocity = 346.41 m/s