Question

#1. Solve for x and y."(3y + 2)°820(10x + 9)O x = 13 and y = 4X = 49 and y = 90O x = 4 and y = 13O x = 4 and y = 49

Answer 1

`\begin{gathered} 2\cdot(10x+9)+82=180\rightarrow10x+9=(98)/(2)=49 \\ 10x+9=49\rightarrow10x=40\rightarrow x=4 \end{gathered}`
`\begin{gathered} 98+2\cdot(3y+2)=180 \\ 2\cdot(3y+2)=82 \\ 3y+2=41 \\ 3y=39 \\ y=13 \end{gathered}`

so the answer is x=4 and y=13