Question

Use the zeros and the labeled point to write the quadratic functionrepresented by the graph.10у(-1,4)-5A. y = x2 + 5x + 6O B. y = 3x2 - 15x + 18O c. y = 2x2 + 10x + 12O D. y = 2x2 + 2x - 12

Answer 1

Observe from the graph that the parabola intersects the x-axis at x=-2 and x=-3.

So -2 and -3 will be the zeroes of the quadratic polynomial.

It means that (x+2) and (x+3) must be the factors of the quadratic polynomial,

So the quadratic equation can be formed as,

`\begin{gathered} y=(x+2)(x+3) \\ y=x(x+3)+2(x+3) \\ y=x^2+3x+2x+6 \\ y=x^2+5x+6 \end{gathered}`

Therefore, option A is the correct choice.