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Annual sales of a certain brand of phone are expected to grow at the rate off' (t) = 0.18t^2+ 0.16t+ 2.64million phones per year. Use a definite integral to determine the total number of phones that will be sold over the next 10 years.

User David Gras
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Given the Annual sales of a certain brand of phones are expected to grow at the rate of:


f^(\prime)(t)=0.18t^2+0.16t+2.64

We will use the definite integral to determine the total number of phones that will be sold over the next 10 years.


\begin{gathered} \int f^(\prime)(t)=\int ^(10)_00.18t^2+0.16t+2.64 \\ \\ =((0.18)/(3)t^3+(0.16)/(2)t^2+2.64t)|^(10) \\ \\ =0.06\cdot10^3+0.08\cdot10^2+2.64\cdot10 \\ =94.4 \end{gathered}

So, the answer will be the number of phones = 94.4 million phones

User Geoffrey Zheng
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