We need to find x in term of j(x).
First, if we move -3 to the left hand side as +3, we have
![j(x)+3=4x](https://img.qammunity.org/2023/formulas/mathematics/college/hl2br44dcu36cfkuc8nopxpnrma2blm8pr.png)
By symmetry, we can write this result as
![4x=j(x)+3](https://img.qammunity.org/2023/formulas/mathematics/college/1dsqz5kyb0n990v9771s7m5clw5eulh4cg.png)
Now, we need to move the coefficient of x to the right hand side. This is given by
![x=(j(x)+3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/jnou7d2cccztqiiq1zrr4nnu3gt7h493om.png)
which can be rewritten as
![x=(j(x))/(4)+(3)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/852res48ztgu8fmg6x58ocq47dh818vaiq.png)
which is the answer.