Solution:
Given:
![w(x)=-(3x)^{(1)/(2)}-4](https://img.qammunity.org/2023/formulas/mathematics/high-school/huy4itz62ou4kxpnp0cgg65fh7iwk041y4.png)
Rewriting the function, by applying the law of fractional exponents,
![a^{(1)/(2)}=√(a)](https://img.qammunity.org/2023/formulas/mathematics/high-school/as9u0f90x4u2mivfbc8tyszyp9qn0e98w2.png)
Hence,
![\begin{gathered} w(x)=-(3x)^{(1)/(2)}-4 \\ w(x)=-√(3x)-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/w0fk3f94rtv0wsvm8e20eqxxqykcsqvw18.png)
The domain of a function is the set of all input values that make the function defined.
The function is undefined when the value of x under the root sign is less than zero because the square root of a negative number is complex.
Hence, the domain exists when x has a value greater than or equal to 0.
Therefore, the domain is;
![Domain:x\ge0](https://img.qammunity.org/2023/formulas/mathematics/high-school/n4dbqmi7cmserscy56twltzqa6pq4s95pn.png)
The range of a function is the set of all output values that makes the function defined.
Hence, the range exists when y is lesser than or equal to minus 4 because a value of y greater than -4, makes the function and domain undefined.
Therefore, the range is;
![Range:w(x)\leq-4](https://img.qammunity.org/2023/formulas/mathematics/high-school/z3r93w736wksowi2eyfnjfvwjxdnkvy7uy.png)