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A committee must be formed with 4 teachers and 4 students. If there are 6 teachers to choose from, and 12 students, how many different ways could the committee be made?

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A committee must be formed with 4 teachers and 4 students. If there are 6 teachers to choose from and 12 students, how many different ways could the committee be made?

step 1

Find out the combination 4C6 (teachers)


4C6=(6!)/(4!(6-4)!)=15

step 2

Find out the combination 4C12 (students)


4C12=(12!)/(4!(12-4)!)=495

step 3

Multiply 15 by 495

15*495=7,425 ways

therefore

the answer is 7,425 ways

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