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which equation describes a line that passes through (-5,-8) and is perpendicular to y=5/4x+10A. y=-0.8x+10B. y=-1.25x-14.25C. y×y=-1.25x-1.75D. y=-0.8x+3

User Tysha
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1 Answer

5 votes

Let's begin by listing out the information given to us:


(x,y)=(-5,-8)

This is perpendicular to the line


y=(5)/(4)x+10

The equation is already in the slope-intercept form:


\begin{gathered} y=(5)/(4)x+10 \\ slope(m)=(5)/(4) \end{gathered}

The slope of the parallel line is given by:


\begin{gathered} m(perpendicular)=-(1)/(m) \\ m=(5)/(4) \\ m(perpendicular)=-(1)/((5)/(4))=-(4)/(5) \\ m(perpendicular)=-(4)/(5)=-0.8 \end{gathered}

We proceed by substituting the values of x & y into the new equation, we have:


undefined

User Krystian Podemski
by
6.0k points
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