Question

which equation describes a line that passes through (-5,-8) and is perpendicular to y=5/4x+10A. y=-0.8x+10B. y=-1.25x-14.25C. y×y=-1.25x-1.75D. y=-0.8x+3

Answer 1

Let's begin by listing out the information given to us:

`(x,y)=(-5,-8)`

This is perpendicular to the line

`y=(5)/(4)x+10`

The equation is already in the slope-intercept form:

`\begin{gathered} y=(5)/(4)x+10 \\ slope(m)=(5)/(4) \end{gathered}`

The slope of the parallel line is given by:

`\begin{gathered} m(perpendicular)=-(1)/(m) \\ m=(5)/(4) \\ m(perpendicular)=-(1)/((5)/(4))=-(4)/(5) \\ m(perpendicular)=-(4)/(5)=-0.8 \end{gathered}`

We proceed by substituting the values of x & y into the new equation, we have: