Question

Three identical lamps are connected in series to a 6.0 V battery. What is the voltage drop across each lamp?

Answer 1

We know that in a series circuit the total voltage is equal to the voltage drop in each component; we also know that the voltage drop in each component is equal to:

`V=IR`

Furthermore, in a series circuit the current in each component is the same.

Let R be the resistance on each lamp, since the current is the same in each of them and they have the same resistance, we have:

`\begin{gathered} V_1+V_2+V_3=V_T \\ \text{ Since all the voltage drops are the same we have:} \\ 3V=6 \\ V=(6)/(3) \\ V=2 \end{gathered}`

Therefore, the voltage drop on each lamp is 2 V