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Solve algebraically for all values of x:25 – 36x336x3 = 0

Solve algebraically for all values of x:25 – 36x336x3 = 0-example-1
User Akkie
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Given:

The objective is to solve the values of x for the equation,


x^5-36x^3=0

The value of x can be calculated by taking x to the power of 3 as common from both the terms.


\begin{gathered} x^3(x^2-36)=0 \\ (x^2-36)=0 \\ x^2=36 \\ x=\sqrt[]{36} \\ x=\pm6 \end{gathered}

Hence, the possibles values of x is +6, -6.

User Sarena
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