Question

Solve algebraically for all values of x:25 – 36x336x3 = 0

Answer 1

Given:

The objective is to solve the values of x for the equation,

`x^5-36x^3=0`

The value of x can be calculated by taking x to the power of 3 as common from both the terms.

`\begin{gathered} x^3(x^2-36)=0 \\ (x^2-36)=0 \\ x^2=36 \\ x=\sqrt[]{36} \\ x=\pm6 \end{gathered}`

Hence, the possibles values of x is +6, -6.