168k views
2 votes
5. Match each equation with the slope m and y-intercept of its graph.5x - 6y = 30 y = 5-6x y = 5/6x +1 5x - by = 6 5x + 6y = 6 6x + y = 12m=-6. y-int= (0,12)m=-6. y-int= (0,5)m = -5/6,int = (0,1)m = 5/6,int = (0,1)Oom = 5/6.int = (0-1)om = 5/6, yint = (0,-5)

5. Match each equation with the slope m and y-intercept of its graph.5x - 6y = 30 y-example-1
User Mattorb
by
7.8k points

1 Answer

3 votes

Hello!

First, we have to remember that the equation of the line has the form:

y = mx + b

• m, = slope

,

• b, = y-intersection

Knowing it, we can solve this exercise:

1st equation: 5x -6y = 30

Let's isolate y:


\begin{gathered} 5x-6y=30 \\ -6y=30-5x \\ -y=(30)/(6)-(5x)/(6) \\ (-1)\cdot-y=5-(5x)/(6)\cdot(-1) \\ y=(5x)/(6)-5 \end{gathered}

Slope: 5/6

Y-intercept: (0, -5)

2nd equation: y = 5 -6x

Slope: -6x

Y-intercept: (0, 5)

3rd equation: y = 5/6x +1

Slope: 5/6

Y-intercept: (0, 1)

4th equation: 5x -6y = 6

Let's isolate y:


\begin{gathered} 5x-6y=6 \\ -6y=6-5x \\ -y=(6)/(6)-(5x)/(6) \\ (-1)\cdot-y=1-(5x)/(6)\cdot(-1) \\ y=(5x)/(6)-1 \end{gathered}

Slope: 5/6

Y-intercept: (0, -1)

5th equation: 5x + 6y = 6

Let's isolate y:


\begin{gathered} 5x+6y=6 \\ 6y=6-5x \\ y=(6)/(6)-(5x)/(6) \\ y=-(5x)/(6)+1 \end{gathered}

Slope: -5/6

Y-intercept: (0, 1)

6th equation: 6x +y = 12


y=-6x+12

Slope: -6

Y-intercept: (0, 12)

Look at your answers below:

5. Match each equation with the slope m and y-intercept of its graph.5x - 6y = 30 y-example-1
User Akkishore
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories