Question

a. pi/3 b. pi/2c. 2pi/3d. 3pi/2 These are 4 options but there can be more than 2 or 3 correct answers.Find the solution of each equation the interval

Answer 1

`\sin x\cdot\cos x-\frac{\sqrt[]{3}}{2}\cos x=0`
`\cos x(\sin x-\frac{\sqrt[]{3}}{2})=0`
`\begin{gathered} \cos x=0 \\ x=(\pi)/(2),(3\pi)/(2) \end{gathered}`
`\begin{gathered} \sin x-\frac{\sqrt[]{3}}{2}=0 \\ \sin x=\frac{\sqrt[]{3}}{2} \\ x=(\pi)/(3) \end{gathered}`

so the answer is pi/2, 3pi/2, and pi/3