Question

How many moles of carbon dioxide are in 26.22 L container at 7.7394 atm and 423 C?

Answer 1

We will assume that the gas behaves like an ideal gas, so we can apply the following equation for ideal gases:

`PV=nRT`

Where,

P is the pressure of the gas in atm, 7.7394 atm

V is the volume of the gas in liters, 26.22L

R is a constant, 0.08206atm.L/mol.K

T is the temperature of the gas in Kelvin, 423°C=696.15K

n is the number of moles

Now, we clear the number of moles and replace the known data:

`n=(RT)/(PV)`
`\begin{gathered} n=(0.08206(atm.L)/(mol.K)*696.15K)/(7.7394atm*26.22L) \\ n=0.2815mol \end{gathered}`

Answer: There are 0.2815 mol of carbon dioxide