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The height of a triangle is 6 cm longer than its base. If its area is 36 square cm, what is the length of the base and the height?

1 Answer

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Given:

There are given that the height of a triangle is 6 cm longer than its base.

Step-by-step explanation:

According to the question.

We need to find the length of the base and the height.

So,

Suppose the height of the triangle is H and the base of the triangle

According to the given data:


H=B+6

Then,

From the area of the triangle:


A=(1)/(2)(B* H)

Then,

Put all the value into the give formula:

So,


\begin{gathered} A=(1)/(2)(B* H) \\ 36*2=(1)/(2)*2* B(B+6) \\ B^2+6B=72 \end{gathered}

Then,


\begin{gathered} B^(2)+6B=72 \\ B^2+6B-72=72-72 \\ B^2+6B-72=0 \end{gathered}

Then,


\begin{gathered} B^(2)+6B-72=0 \\ (B+12)(B-6)=0 \\ B=-12;B=6 \end{gathered}

Then,

According to the concept, the value of the base cannot be negative.

So,

The value of the base is:


B=6

Now,

From the give statement:


\begin{gathered} H=B+6 \\ H=6+6 \\ H=12 \end{gathered}

Final answer:

Hence, the base of the triangle is 6 and the height of the triangle is 12.

User Tarun Upadhyay
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