Recall that two lines are perpendicular if the product of their slopes is equal to -1.
Notice that f(x) is given in slope-intercept form, then, the slope of f(x) is 3. Therefore, the slope of g(x) must be
![-(1)/(3)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/1qmfpsg9cqgaui7ru46nyip9ywd02byizz.png)
Now, to determine the equation of g(x) we will use the following formula:
![y(x)-y_0=m(x-x_0),](https://img.qammunity.org/2023/formulas/mathematics/college/qbvdz4nbkrruvrlgzcdousyrtuk2565ful.png)
where (x₀,y₀) is a point on the line, and m is the slope.
Substituting m=-1/3 and (x₀,y₀)=(3,1), we get:
![g(x)-1=-(1)/(3)(x-3)\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/dsdeb9v9xonjec35okuful5fa1tbgxqb19.png)
Taking the above equation to its slope-intercept form we get:
![g(x)=-(1)/(3)x+2.](https://img.qammunity.org/2023/formulas/mathematics/college/ywhbxsudlgjvn9v1gks95zl18s1hpkgrb4.png)
Answer:
Slope:
![-(1)/(3)=-0.33\text{.}](https://img.qammunity.org/2023/formulas/mathematics/college/v3cw0mf5acf1pqh9i8jz655gt4cc5834sf.png)
Equation:
![\begin{gathered} g(x)=-(1)/(3)x+2. \\ g(x)=-0.33x+2. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gg7dk0x4hoq9w90iycts1hwypl50ztv1lv.png)