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ABCD is a rhombus fbnc equals 4x - 5 + C + D equals 2 as + 7 find X

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We are given the dimensions of a rhombus. Thought it's not said, we'll assume the sides have the same length, so we can find the value of x, since no more conditions are provided

BC=4x-5

CD=2x+7

Since BC=CD


4x-5=2x+7

Adding 5


4x=2x+7+5=2x+12

subtracting 2x:


4x-2x=12\Rightarrow\text{ 2x=12}

Solving:

x=12/2=6

x=6

Option D. x=6

User AtomicPorkchop
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