We are given the dimensions of a rhombus. Thought it's not said, we'll assume the sides have the same length, so we can find the value of x, since no more conditions are provided
BC=4x-5
CD=2x+7
Since BC=CD
![4x-5=2x+7](https://img.qammunity.org/2023/formulas/mathematics/high-school/ti1ygqh2imazm115mx1dy6cuua8jhqdg75.png)
Adding 5
![4x=2x+7+5=2x+12](https://img.qammunity.org/2023/formulas/mathematics/high-school/3swxnkkfw3i12cf1cw5w9ji3cy48n1k4qh.png)
subtracting 2x:
![4x-2x=12\Rightarrow\text{ 2x=12}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ciyja53ij27336ht8h9w64lx1earjvin3k.png)
Solving:
x=12/2=6
x=6
Option D. x=6