Question

assuming you have a 1.3M (molarity) solution of HNO3If you began with 0.6 liters of solution, and diluted the solution to a concentration of 0.45M, whatwould the final volume of the solution be?

Answer 1

The final volume of the solution be 2.13 liters

Step-by-step explanation

Given:

Molarity of the stock HNO3 solution, C₁ = 1.3 M

Volume of the stock HNO3 solution, V₁ = 0.6 L

Molarity of the dilute HNO3 solution, C₂ = 0.45 M

What to find:

The final volume of the solution (i.e the volume of the dilute HNO3 solution, V₂)

Step-by-step solution:

The final volume of the solution can be calculated using the dilution formula.

`\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow V_2=(C_1V_1)/(C_2) \end{gathered}`

Plugging the values of the given parameters into the formula, we have;

`V_2=(1.3M*0.6L)/(0.45M)=(0.96L)/(0.45)=2.13\text{ }L`

Therefore, the final volume of the solution be 2.13 liters